document.write( "Question 1012103: What is the area of a rectangle whose sides are twice as long as the sides of a smaller rectangle whose area is 17cm^2. \n" ); document.write( "

Algebra.Com's Answer #627958 by ValorousDawn(53) $\"\"$ $\"About$

You can put this solution on YOUR website!
The area of rectangle is given by the formula $\"a=b%2Ah\"$ . If both sides, base and height, are longer, then the equation is now $\"a=2b%2A2h\"$ which equates to $\"4b%2Ah\"$ . This tells us we have four times the area of the original rectangle. Thus, $\"4%2A17=68\"$
\n" ); document.write( "Therefore, your answer is 68 $\"cm%5E2\"$ \n" ); document.write( "

\n" );