document.write( "Question 1012085: I have to factor the polynomial completely (a) over the real numbers, and (b) over the complex numbers.
\n" ); document.write( "X to the third power + 4x to the second power + 5x\r
\n" ); document.write( "\n" ); document.write( "I started with x(x squared +4x+5) i know that x=0 is a real root. But there are no real factors of 5 that add up to 4? So what do i do?
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Algebra.Com's Answer #627937 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\"x%5E3%2B+4x+%5E2%2B+5x\"\r
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\n" ); document.write( "\n" ); document.write( " =\"x%28x%5E2%2B+4x+%2B+5%29\"\r
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\n" ); document.write( "\n" ); document.write( "=\"x%28x%5E2%2B+4x+%2B+5%29\"......use quadratic formula to find the roots of \"x%5E2%2B+4x+%2B+5\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\" \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-4+%2B-+sqrt%28+4%5E2-4%2A1%2A5+%29%29%2F%282%2A1%29+\" \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-4+%2B-+sqrt%28+16-20+%29%29%2F2+\" \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-4+%2B-+sqrt%28+-4+%29%29%2F2+\" \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-4+%2B-+2i%29%2F2+\" \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-cross%284%292+%2B-+cross%282%29i%29%2Fcross%282%29+\" \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%282+%2B-i%29+\"\r
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\n" ); document.write( "\n" ); document.write( "roots: \"x+=+%282+%2Bi%29+\" and \"x+=+%282+-i%29+\"\r
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\n" ); document.write( "\n" ); document.write( "use their product rule and you have \"%28x%2B+%282+%2Bi%29%29\" and \"%28x%2B%282+-i%29%29+\"\r
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\n" ); document.write( "\n" ); document.write( "so, to continue with factoring, we have\r
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\n" ); document.write( "\n" ); document.write( "=\"x%28x%2B+%282+%2Bi%29%29%28x%2B%282+-i%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "=\"x%28x%2B+2+%2Bi%29%28x%2B2+-i%29\"\r
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