document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1012071>Question 1012071</A>: <I><SPAN STYLE=\"word-break: break-all;\"> So the question is as follows:\r<BR>\n" );
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document.write( "\"If log 2 + 0.301 and log 3 + 0.447, find each of the following using only these values and the properties of logarithms. Show your work.\r<BR>\n" );
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document.write( "a. log 6<BR>\n" );
document.write( "b. log (2/3)<BR>\n" );
document.write( "c. log 1.5<BR>\n" );
document.write( "d. log 18\"\r<BR>\n" );
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document.write( "my teacher stopped teaching the lessons because we have a limited time before exams, so she started assigning videos to watch. I watched the assigned ones, and many more but I just don't understand the question, I don't even really know what it's asking me to do. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #627923 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=627923\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I'm assuming you meant to write this\r<BR>\n" );
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document.write( "log(2) = 0.301<BR>\n" );
document.write( "log(3) = 0.477\r<BR>\n" );
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document.write( "I used a calculator to compute those above\r<BR>\n" );
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document.write( "We will use these log rules\r<BR>\n" );
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document.write( "(1) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%28%28x%2Ay%29%29+=+log%28%28x%29%29%2Blog%28%28y%29%29 ALIGN=MIDDLE  ALT=\"log%28%28x%2Ay%29%29+=+log%28%28x%29%29%2Blog%28%28y%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "(2) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%28%28x%2Fy%29%29+=+log%28%28x%29%29-log%28%28y%29%29 ALIGN=MIDDLE  ALT=\"log%28%28x%2Fy%29%29+=+log%28%28x%29%29-log%28%28y%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "(3) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%28%28x%5Ey%29%29+=+y%2Alog%28%28x%29%29 ALIGN=MIDDLE  ALT=\"log%28%28x%5Ey%29%29+=+y%2Alog%28%28x%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "--------------------------------------------------------------------\r<BR>\n" );
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document.write( "a)\r<BR>\n" );
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document.write( "log(6) = log(2*3)\r<BR>\n" );
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document.write( "log(6) = log(2) + log(3) ... Use rule 1 (see above)\r<BR>\n" );
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document.write( "log(6) = 0.301 + 0.477\r<BR>\n" );
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document.write( "log(6) = 0.778\r<BR>\n" );
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document.write( "b)\r<BR>\n" );
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document.write( "log(2/3) = log(2) - log(3) ... Use rule 2 (see above)\r<BR>\n" );
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document.write( "log(2/3) = 0.301 - 0.477\r<BR>\n" );
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document.write( "log(2/3) = -0.176\r<BR>\n" );
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document.write( "c)\r<BR>\n" );
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document.write( "log(1.5) = log(3/2)\r<BR>\n" );
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document.write( "log(1.5) = log(3) - log(2) ... Use rule 2 (see above)\r<BR>\n" );
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document.write( "log(1.5) = 0.477 - 0.301\r<BR>\n" );
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document.write( "log(1.5) = 0.176\r<BR>\n" );
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document.write( "d)\r<BR>\n" );
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document.write( "log(18) = log(2*9)\r<BR>\n" );
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document.write( "log(18) = log(2*3^2)\r<BR>\n" );
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document.write( "log(18) = log(2)+log(3^2) ... Use rule 1 (see above)\r<BR>\n" );
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document.write( "log(18) = log(2)+2*log(3) ... Use rule 3 (see above)\r<BR>\n" );
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document.write( "log(18) = 0.301 + 2*0.477\r<BR>\n" );
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document.write( "log(18) = 1.255\r<BR>\n" );
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document.write( "All answers are approximate </SPAN>\n" );
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