document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1012071>Question 1012071</A>: <I><SPAN STYLE=\"word-break: break-all;\"> So the question is as follows:\r<BR>\n" );
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document.write( "\"If log 2 + 0.301 and log 3 + 0.447, find each of the following using only these values and the properties of logarithms. Show your work.\r<BR>\n" );
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document.write( "a. log 6<BR>\n" );
document.write( "b. log (2/3)<BR>\n" );
document.write( "c. log 1.5<BR>\n" );
document.write( "d. log 18\"\r<BR>\n" );
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document.write( "my teacher stopped teaching the lessons because we have a limited time before exams, so she started assigning videos to watch. I watched the assigned ones, and many more but I just don't understand the question, I don't even really know what it's asking me to do. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #627922 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=627922\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I think it should read:<BR>\n" );
document.write( "\"If log 2 = 0.301 and log 3 + 0.477, find each of the following using only these values and the properties of logarithms.<BR>\n" );
document.write( "a. log 6 <BR>\n" );
document.write( "log(2*3) = log(2)+log(3), when multiplying two numbers you add their logs<BR>\n" );
document.write( "therefore<BR>\n" );
document.write( "log(6) = .301+.447 = .778<BR>\n" );
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document.write( "b. log (2/3) when dividing you subtract their logs<BR>\n" );
document.write( "log(2/3) = log(2) - log(3)<BR>\n" );
document.write( "log(2/3) = .301 - .477 = -.156<BR>\n" );
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document.write( "c. log 1.5<BR>\n" );
document.write( "1.5 = (3/2)<BR>\n" );
document.write( "log(3/2) = .477 - .301 = .176<BR>\n" );
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document.write( "d. log 18\"<BR>\n" );
document.write( "same as <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%28%283%5E2%2A2%29%29 ALIGN=MIDDLE  ALT=\"log%28%283%5E2%2A2%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, when raising a power you multiply log by the exponent<BR>\n" );
document.write( "log(18) = 2(.477) + .301 = .954 + .301 = 1.255<BR>\n" );
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document.write( "Did this give you some idea of what is going here?  </SPAN>\n" );
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