document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=86767>Question 86767</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The hypotenuse of a right triangle is 2.8 units long. The longer leg is 1.6 units longer than the shorter leg. Find the lengths of the sides of the triangle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #62792 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=62792\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2.8^2=X^2+(X+1.6)^2<BR>\n" );
document.write( "7.84=X^2+X^2+3.2X+2.56<BR>\n" );
document.write( "2X^2+3.2X+2.56-7.84=0<BR>\n" );
document.write( "2X^2+3.2X-5.28=0<BR>\n" );
document.write( "2(X^2+1.6X-2.64)=0<BR>\n" );
document.write( "USING THE QUADRATIC EQUATION WE GET<BR>\n" );
document.write( "X=(-1.6+-SQRT[1.6^2-4*1*-2.64])/281<BR>\n" );
document.write( "X=(-1.6+-SQRT[2.56+10.56])/2<BR>\n" );
document.write( "X=(-1.6+-SQRT13.12)/2<BR>\n" );
document.write( "X=(-1.6+-3.622)/2<BR>\n" );
document.write( "X=(-1.6+3.622)/2<BR>\n" );
document.write( "X=2.022/2<BR>\n" );
document.write( "X=1.011 ANSWER.<BR>\n" );
document.write( "X=(-1.6-3.622)/2<BR>\n" );
document.write( "X=-5.244/2<BR>\n" );
document.write( "X=2.611 ANSWER. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );