document.write( "Question 1012045: The 250 soldiers in a camp had enough food for forty days, After 10 days, 50 soldiers joined them. For how long will the remaining food last them? Solve using variation. \n" ); document.write( "
Algebra.Com's Answer #627909 by MathTherapy(10551)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "The 250 soldiers in a camp had enough food for forty days, After 10 days, 50 soldiers joined them. For how long will the remaining food last them? Solve using variation.
\n" ); document.write( "
Let S be number of soldiers, k = constant of variation, j = amount of food, and T = time 
\n" ); document.write( "\"S+=+k%28j%29%2FT\"
\n" ); document.write( "\"250+=+k%281%29%2F40\"
\n" ); document.write( "\"250+=+k%2F40\"
\n" ); document.write( "k = 250(40), or 10,000\r
\n" ); document.write( "\n" ); document.write( "Let fraction consumed after 10 days, be j
\n" ); document.write( "\"S+=+k%28j%29%2FT\"
\n" ); document.write( "\"250+=+10000%28j%29%2F10\"
\n" ); document.write( "\"250+=+10000j%2F10\"
\n" ); document.write( "\"250+=+1000j\"
\n" ); document.write( "j, or fraction consumed after 10 days = \"250%2F1000\", or \"1%2F4\"\r
\n" ); document.write( "\n" ); document.write( "With \"1%2F4\" of food consumed \"3%2F4\" remains, and 300 (250 + 50) soldiers are in camp
\n" ); document.write( "\"S+=+k%28j%29%2FT\"
\n" ); document.write( "\"300+=+10000%283%2F4%29%2FT\"
\n" ); document.write( "\"300+=+7500%2FT\"
\n" ); document.write( "300T = 7,500 ------- Cross-multiplying
\n" ); document.write( "T, or time the remaining \"3%2F4\" of food will last = \"7500%2F300\", or \"highlight_green%2825%29\" days \n" ); document.write( "
\n" );