document.write( "Question 1012022: How many minutes after 5 o’clock, will the minute hand be 16 minute spaces behind the hour hand? \n" ); document.write( "
Algebra.Com's Answer #627900 by Theo(13342)![]() ![]() You can put this solution on YOUR website! at 5 o'clock, the hour hand is at the 25 minute mark and the minute hand is at the 0 minute mark.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "at 6 o'clock, the hour hand is at the 30 minute mark and the minute hand is at the 0 minute mark, or at the 60 minute mark, depending on how you want to look at it.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "based on this, we can develop a formula for the hour hand versus the minute hand.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "hour hand in terms of minutes = 25 + x/12.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "minute hand in terms of minutes = x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "based on this formula, we can determine the position of the hour hand in terms of minutes.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when x = 0, the hour hand is at the 25 + 0/12 = 25 minute mark.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when x = 60, the hour hand is at the 25 + 60/12 = 30 minute mark.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this tracks with what we know, because at 5 o'clock, the hour hand is at the 25 minute mark and at 6 o'clock, the hour hand is at the 30 minute mark.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so now we want to find out at how many minutes will the hour hand be 16 minutes behind the hour hand.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "our formula becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "25 + x/12 - x = 16\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that says that the difference of the position of the hour hand in minutes minus the position of the minute hand must be equal to 16.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if we solve for x, we will find that x = 9.81818...\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when x = 9.81818..., 25 + x/12 = 25 + 9.81818.../12 = 25.81818....\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the difference between the hour hand in terms of minutes a and the minute hand is 25.81818... - 9.81818... = 16.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "in 9.81818... minutes after 5:00 o'clock, the hour hand and the minute hand will be exactly 16 minutes apart, with the minute hand being behind the hour hand.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |