document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1012045>Question 1012045</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The 250 soldiers in a camp had enough food for forty days, After 10 days, 50 soldiers joined them. For how long will the remaining food last them? Solve using variation. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #627883 by </B><A HREF=/tutors/aboutme.mpl?userid=ValorousDawn><B>ValorousDawn(53)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ValorousDawn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ValorousDawn><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=627883\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I don't even think variation is a legitimate way to solve this problem but here's something.<BR>\n" );
document.write( "Lets say each soldier eats 1 food unit every day. Forty days for 250 soldiers is 10,000 food units. After 10 days, they are down to 10,000-250*10=8,750. If there are now <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=250%2B50=300+soldiers ALIGN=MIDDLE  ALT=\"250%2B50=300+soldiers\"   DISABLED_style= \"max-width:90%; height:auto;\" >, they then subsequently will eat 300 food units a day. They will have food for <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=8750%2F300=29.16 ALIGN=MIDDLE  ALT=\"8750%2F300=29.16\"   DISABLED_style= \"max-width:90%; height:auto;\" > days. If you must round, you'd round down, for 29 days. </SPAN>\n" );
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