document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1012046>Question 1012046</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If f(x)=ax^2-12x+c and f(-3/2)=8 is the maximum value, find the values of a and c. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #627877 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=627877\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If f(x)=ax^2-12x+c and f(-3/2)=8 is the maximum value, <BR>\n" );
document.write( "find the values of a and c.<BR>\n" );
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document.write( "Max occurs at x = -b/(2a)<BR>\n" );
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document.write( "Therefore:: -b/(2a) = -3/2<BR>\n" );
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document.write( "b = -12<BR>\n" );
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document.write( "12/(2a) = -3/2<BR>\n" );
document.write( "-6a = 24<BR>\n" );
document.write( "a = -4<BR>\n" );
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document.write( "Using (-3/2,8), solve for \"c\"::<BR>\n" );
document.write( "-4(-3/2)^2 - 12(-3/2) + c = 8<BR>\n" );
document.write( "----<BR>\n" );
document.write( "-9 + 18 + c = 8<BR>\n" );
document.write( "c = -1<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( "  </SPAN>\n" );
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