document.write( "Question 86784: MAY I PLEASE GET SOME HELP WITH THESE I REALLY NEED HELP\r
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document.write( "A regular squre pryramid with slant height 9 and base edge 6
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document.write( "(a)lateral area
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document.write( "(b)the total area\r
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document.write( "A right cylinder with radius 3 and height 7
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document.write( "(a)lateral area
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document.write( "(b) the total area\r
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document.write( "Two circles have area of 49pi and 36pi. Find the ratio of their radii. \n" );
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Algebra.Com's Answer #62784 by Flake(45)![]() ![]() ![]() You can put this solution on YOUR website! You need to understand the terms \"lateral Area\" and \"Total Area\". Once understand that, it should be pretty straight forward.\r \n" ); document.write( "\n" ); document.write( "A regular squre pryramid with slant height 9 and base edge 6 \n" ); document.write( "a) Lateral Area for regular pryramid = 1/2*(perimeter of the base)*(slant height) \n" ); document.write( "-----slant height is given, you need to find the perimeter for the square base\r \n" ); document.write( "\n" ); document.write( "b) the total area = lateral area + base area \n" ); document.write( "----- you know the lateral area from \"a\". You should know the area for a square base\r \n" ); document.write( "\n" ); document.write( "------------------------ \n" ); document.write( "A right cylinder with radius 3 and height 7 \n" ); document.write( "a) Lateral Area = (height) * (circumference of the base) \n" ); document.write( "---------- height is given. The circumference of a cone is a circle. You need to calculate the circumference of a circle whose radius is 3\r \n" ); document.write( "\n" ); document.write( "b) the total area = lateral area + base areas \n" ); document.write( "----- you know the lateral area from \"a\". You should how to calculate the area of a circle base. \n" ); document.write( "------ remember a cone has 2 circle bases. One on the bottom the other is the top.\r \n" ); document.write( "\n" ); document.write( "--------------- \n" ); document.write( "Two circles have area of 49pi and 36pi. Find the ratio of their radii. \n" ); document.write( "Let R#1 be radius#1. \n" ); document.write( "Let R#2 be radius#2. \n" ); document.write( "Radio = R#1/R#2 \n" ); document.write( "---Find R#1: Area of circle=(pi)(R^2) \n" ); document.write( "So 49pi=(pi)(R#1^2) \n" ); document.write( "So 49=R#1^2 \n" ); document.write( "So R#1 = sqrt of 49 \n" ); document.write( "-----Now repeat to find R#2 and find ratio \n" ); document.write( " |