document.write( "Question 1011999: the length of a rectangle is 5 1/3 cm more than the width.the perimeter is 56 cm.Find the width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #627838 by macston(5194)\"\" \"About 
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\n" ); document.write( "W=width; L=length=W+5 1/3
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\n" ); document.write( "P=2(L+W)
\n" ); document.write( "56cm=2(L+W)
\n" ); document.write( "28cm=L+W
\n" ); document.write( "28cm=(W+5 1/3cm)+W
\n" ); document.write( "22 2/3cm=2W
\n" ); document.write( "11 1/3 cm=W
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\n" ); document.write( "ANSWER: The width of the rectangle is 11 1/3 cm..
\n" ); document.write( "CHECK:
\n" ); document.write( "L=W+5 1/3 cm
\n" ); document.write( "L=11 1/3 cm+ 5 1/3 cm=16 2/3 cm
\n" ); document.write( "P=2(L+W)
\n" ); document.write( "56 cm = 2(16 2/3 cm+ 11 1/3 cm)
\n" ); document.write( "56 cm = 2(28cm)
\n" ); document.write( "56 cm = 56cm
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