document.write( "Question 1011994: Janice has 93 cents. She has a total of nine coins. If she doesn't have a half dollar, how many of each coin does she have?\r
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Algebra.Com's Answer #627828 by macston(5194)\"\" \"About 
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\n" ); document.write( "She must have 3 pennies. If she hah more, she must have at least 8,
\n" ); document.write( "Then she would have to have $0.85 in one coin.
\n" ); document.write( "So she has 3 pennies.
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\n" ); document.write( "So she has $0.90 in 6 coins (nickels, dimes, and quarters)
\n" ); document.write( "She must have at least 2 quarters. If she only had one, she would have to
\n" ); document.write( "have $0.65 in 5 coins, and 5 dimes is only $0.50.
\n" ); document.write( "If she has 2 quarters, she needs 40 cents in four coins,
\n" ); document.write( "or four dimes and no nickels.
\n" ); document.write( "If she has 3 quarters, she needs fifteen cents in three coins,
\n" ); document.write( "or three nickels and no dimes.
\n" ); document.write( "If she has 4 quarters, she has more than 93 cents.
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\n" ); document.write( "The possibilities are:
\n" ); document.write( "3 pennies, three nickels, and three quarters
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\n" ); document.write( "3 pennies, four dimes, and two quarters
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