document.write( "Question 1011968: A stone is thrown straight up from the ground. The height above the ground, h(t) metres is a function of time, t seconds (t >0) according to the rule h(t) = 20t - 5t^2. Find:\r
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document.write( "a. the domain of h\r
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document.write( "I do not understand how to acquire the domain of the function. Can you please explain how to get to the answer of 0 < t < 4\r
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document.write( "b. the greatest height achieved
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document.write( "I solved this part: \r
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document.write( "-5t^2 + 20t + 0
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document.write( "-5(t^2 - 4t) + 0
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document.write( "-5(t^2 - 4t + 4) + 20
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document.write( "-5( t - 2)^2 +20\r
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document.write( "So the maximum distance is 20
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Algebra.Com's Answer #627819 by macston(5194)![]() ![]() You can put this solution on YOUR website! The domain (possible t values) must be greater than zero \n" ); document.write( "because t is time of the stone in air and in this case \n" ); document.write( "negative time has no meaning. \n" ); document.write( "The stone will be thrown and will hit the ground again, \n" ); document.write( "and time in air will again be meaningless. The stone will \n" ); document.write( "hit the ground when the height (h(t)) is zero again so: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "When h(t)=0: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "So the only valid times when the rock is in the air are between \n" ); document.write( "t=0 (when the stone is thrown) and t=4 (when the stone lands). \n" ); document.write( "Any other values give a negative height. \n" ); document.write( " \n" ); document.write( " |