document.write( "Question 1011968: A stone is thrown straight up from the ground. The height above the ground, h(t) metres is a function of time, t seconds (t >0) according to the rule h(t) = 20t - 5t^2. Find:\r
\n" ); document.write( "\n" ); document.write( "a. the domain of h\r
\n" ); document.write( "\n" ); document.write( "I do not understand how to acquire the domain of the function. Can you please explain how to get to the answer of 0 < t < 4\r
\n" ); document.write( "\n" ); document.write( "b. the greatest height achieved
\n" ); document.write( "I solved this part: \r
\n" ); document.write( "\n" ); document.write( "-5t^2 + 20t + 0
\n" ); document.write( "-5(t^2 - 4t) + 0
\n" ); document.write( "-5(t^2 - 4t + 4) + 20
\n" ); document.write( "-5( t - 2)^2 +20\r
\n" ); document.write( "\n" ); document.write( "So the maximum distance is 20
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Algebra.Com's Answer #627819 by macston(5194)\"\" \"About 
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The domain (possible t values) must be greater than zero
\n" ); document.write( "because t is time of the stone in air and in this case
\n" ); document.write( "negative time has no meaning.
\n" ); document.write( "The stone will be thrown and will hit the ground again,
\n" ); document.write( "and time in air will again be meaningless. The stone will
\n" ); document.write( "hit the ground when the height (h(t)) is zero again so:
\n" ); document.write( ".
\n" ); document.write( "\"h%28t%29=20t-5t%5E2\"
\n" ); document.write( ".
\n" ); document.write( "When h(t)=0:
\n" ); document.write( "\"0=20t-5t%5E2\"
\n" ); document.write( "\"0=%28t%29%2820-5t%29\"
\n" ); document.write( "\"t=0\" \"OR\" \"20-5t=0\"
\n" ); document.write( "\"t=0\" \"OR\" \"20=5t\"
\n" ); document.write( "\"t=0\" \"OR\" \"4=t\"
\n" ); document.write( ".
\n" ); document.write( "So the only valid times when the rock is in the air are between
\n" ); document.write( "t=0 (when the stone is thrown) and t=4 (when the stone lands).
\n" ); document.write( "Any other values give a negative height.
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