document.write( "Question 1011972: In ΔABC, AB = CB and D is on AB such that AC = DC. If m∠ADC = 75, what is m∠B?\r
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\n" ); document.write( "\n" ); document.write( "Sorry if its messy, but I attempted it and got stuck. My work so far was that if CA is congruent to CD then the triangle is isosceles so therefore ∠CAD is congruent to ∠CDA. Because ∠CDA was given as 75 degrees in the given I also know ∠CAD is 75 degrees. Also because ∠CDA and ∠CDB form a linear pair, they are also supplementary so I subtract 75 (∠CDB) from 180 to get ∠CDB which is 105. As I know the interior angles add up to the exterior angle I did 105 - 75 which gives me ∠ACD which is 30 degrees. \r
\n" ); document.write( "\n" ); document.write( "This is where I get stuck and have no idea how to find ∠B. I do not think I can use the ext. angle thm. as I do not know ∠DCB. Please help me out!
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Algebra.Com's Answer #627800 by macston(5194)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "Triangle ABC is isosceles, with angle CAB=angle ACB.
\n" ); document.write( "Triangle ADC is isosceles with angle CAD=angle CDA.
\n" ); document.write( "Given angle CDA=75 degrees, angles CAB (∠A) and ACB (∠C) also equal 75 degrees.
\n" ); document.write( "Angles CAB (∠A), and CBA (∠B), ACB (∠C) form the triangle ABC,
\n" ); document.write( "thus their sum is 180 degrees:
\n" ); document.write( "∠A + ∠B + ∠C = 180 degrees
\n" ); document.write( "75 degrees + ∠B + 75 degrees = 180 degrees
\n" ); document.write( "∠B = 30 degrees
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\n" ); document.write( "ANSWER The measure of Angle B is 30 degrees.
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