document.write( "Question 86770This question is from textbook algebra structure and method
\n" ); document.write( ": I'm supposed to solve this by using the substitution method and check it.
\n" ); document.write( "I'm not sure how to do this one
\n" ); document.write( "x=1/5y
\n" ); document.write( "3x+2y=26
\n" ); document.write( "I would appreciate the help \n" ); document.write( "
Algebra.Com's Answer #62777 by tutorcecilia(2152)\"\" \"About 
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x=1/5y
\n" ); document.write( "3x+2y=26
\n" ); document.write( ".
\n" ); document.write( "Replace x=1/5y for x in the second equation and simplify\"
\n" ); document.write( "3(1/5y)+2y=26
\n" ); document.write( "3/5y+2y=26
\n" ); document.write( "3/5y+10/5y=26
\n" ); document.write( "13/5y=26
\n" ); document.write( ".
\n" ); document.write( "(5/13)(13/5)y=(5/13)(26)
\n" ); document.write( "y=130/13
\n" ); document.write( "y=10
\n" ); document.write( ".
\n" ); document.write( "Solve for the x-term by plugging (y=10) back into either equation:
\n" ); document.write( "3x+2y=26
\n" ); document.write( "3x+2(10)=26
\n" ); document.write( "3x+20=26
\n" ); document.write( "3x+20-20=26-20
\n" ); document.write( "3x=6
\n" ); document.write( "3x/3=6/3
\n" ); document.write( "x=2
\n" ); document.write( ".
\n" ); document.write( "checking:
\n" ); document.write( "3x+2y=26
\n" ); document.write( "3(2)+2(10)=26
\n" ); document.write( "6+20=26
\n" ); document.write( "26=26 [checks out]
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