document.write( "Question 86765: Hi,
\n" ); document.write( "I am working on a quadratic equation: x^2 + 4x + 4 = 7. \r
\n" ); document.write( "\n" ); document.write( "I'm not sure if I've arrived at the correct answer...I have x = 2(plus/minus) sq.rt. 7....am I correct in thinking this is the final answer? \r
\n" ); document.write( "\n" ); document.write( "Thank you!
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Algebra.Com's Answer #62775 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
You are almost absolutely correct! The two in your answer should be negative.
\n" ); document.write( "Starting with:
\n" ); document.write( "\"x%5E2+%2B+4x+%2B+4+=+7\" Subtract 7 from both sides to get your equation into the standard form:\"ax%5E2%2Bbx%2Bc+=+0\"
\n" ); document.write( "\"x%5E2%2B4x-3+=+0\" Applying the quadratic formula: \"x+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a\" you'll get:
\n" ); document.write( "\"x+=+%28-4%2B-sqrt%284%5E2-4%281%29%28-3%29%29%29%2F2%281%29\" Simplifying this:
\n" ); document.write( "\"x+=+%28-4%2B-sqrt%2816-%28-12%29%29%29%2F2\"
\n" ); document.write( "\"x+=+%28-4%2B-sqrt%2828%29%29%2F2\" Simplifying further:
\n" ); document.write( "\"x+=+%28-4%2B-sqrt%284%2A7%29%29%2F2\"
\n" ); document.write( "\"x+=+%28-4%2B-2%2Asqrt%287%29%29%2F2\" This should show + or -
\n" ); document.write( "\"x+=+-2%2Bsqrt%287%29\" or \"x+=+-2-sqrt%287%29\"
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