document.write( "Question 1011920: A bank teller has P20 and P50 bills. The number of P50 bills is 7 less than twice the number of P20 bills. If she has a total of P1090. How many P20 and P50 bills are there? \n" ); document.write( "
Algebra.Com's Answer #627747 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "X=number of P20 bills; Y=number of P50 bills=2X-7 \n" ); document.write( ". \n" ); document.write( "P20(X)+P50(Y)=P1090 \n" ); document.write( "20x+50(2X-7)=1090 \n" ); document.write( "20X+100X-350=1090 \n" ); document.write( "120X=1440 \n" ); document.write( "X=12 \n" ); document.write( "ANSWER 1: There are twelve P20 bills. \n" ); document.write( ". \n" ); document.write( "Y=2X-7=2(12)-7=24-7=17 \n" ); document.write( "ANSWER 2: There are seventeen P50 bills. \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( "P20(X)+P50(Y)=P1090 \n" ); document.write( "P20(12)+P50(17)=P1090 \n" ); document.write( "P240+P850=P1090 \n" ); document.write( "P1090=P1090 \n" ); document.write( " \n" ); document.write( " |