document.write( "Question 1011920: A bank teller has P20 and P50 bills. The number of P50 bills is 7 less than twice the number of P20 bills. If she has a total of P1090. How many P20 and P50 bills are there? \n" ); document.write( "
Algebra.Com's Answer #627747 by macston(5194)\"\" \"About 
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\n" ); document.write( "X=number of P20 bills; Y=number of P50 bills=2X-7
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\n" ); document.write( "P20(X)+P50(Y)=P1090
\n" ); document.write( "20x+50(2X-7)=1090
\n" ); document.write( "20X+100X-350=1090
\n" ); document.write( "120X=1440
\n" ); document.write( "X=12
\n" ); document.write( "ANSWER 1: There are twelve P20 bills.
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\n" ); document.write( "Y=2X-7=2(12)-7=24-7=17
\n" ); document.write( "ANSWER 2: There are seventeen P50 bills.
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\n" ); document.write( "CHECK:
\n" ); document.write( "P20(X)+P50(Y)=P1090
\n" ); document.write( "P20(12)+P50(17)=P1090
\n" ); document.write( "P240+P850=P1090
\n" ); document.write( "P1090=P1090
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