document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1011918>Question 1011918</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A cylinder is inscribed in a sphere of radius 1. Express the volume V of the cylinder as a function of the base radius r.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #627741 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39621)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=627741\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Make a circle on cartesian system, radius of the circle, 1.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2By%5E2=1 ALIGN=MIDDLE  ALT=\"x%5E2%2By%5E2=1\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "x will be the radius of the CYLINDER.<BR>\n" );
document.write( "The cylinder height will be  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=sqrt%281-x%5E2%29 ALIGN=MIDDLE  ALT=\"y=sqrt%281-x%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "That only gives you a figure for the largest cross section; but you want VOLUME, so....\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=v=y%2Api%2Ax%5E2 ALIGN=MIDDLE  ALT=\"v=y%2Api%2Ax%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, because the base radius for the cylinder is x.<BR>\n" );
document.write( "Substitute for y.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28v=pi%2Ax%5E2%2Asqrt%281-x%5E2%29%29 ALIGN=MIDDLE  ALT=\"highlight%28v=pi%2Ax%5E2%2Asqrt%281-x%5E2%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >-----No really - My mistake was to forget accounting for both parts of what make the \"height\".  This would be 2y, instead of just y.  The tutor iklyen gave the correct answer, result. </SPAN>\n" );
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