document.write( "Question 1011890: a person invests rs 1000 at 10% compound interest of two years.then he invests the maturity amount for 1 year at10% compound interest for compounded half-yearly. what is the total amount he receives at the end of three years \n" ); document.write( "
Algebra.Com's Answer #627704 by addingup(3677)![]() ![]() You can put this solution on YOUR website! the formula for compound interest is: \n" ); document.write( "A= P(1+r/n)^nt \n" ); document.write( "where: \n" ); document.write( "A is the final amount \n" ); document.write( "P is the initial investment (rs 1000) \n" ); document.write( "r is the interest rate (10%/100= 0.10) \n" ); document.write( "n is the number of periods (compounded half yearly will be 2 periods) \n" ); document.write( "and finally, the exponent: \n" ); document.write( "nt is the number of periods times the number of years \n" ); document.write( "Since I don't understand \"interest of two years\" and I don't want to give you a bad answer, please plug in the numbers in the above formula and work your calculator to get your answers. \n" ); document.write( "J \n" ); document.write( " |