document.write( "Question 1011881: An amount of P340000 is invested, part at 8% and the remainder at 9%. Find the amount invested at each rate if the yearly income on each investment is the same. \n" ); document.write( "
Algebra.Com's Answer #627698 by Theo(13342)\"\" \"About 
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x = part invested at 8%.
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\n" ); document.write( "\n" ); document.write( "x + y = 340,000\r
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\n" ); document.write( "\n" ); document.write( ".08x = .09y\r
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\n" ); document.write( "\n" ); document.write( "solve for x to get x = .09y/.08 which becomes x = 1.125y\r
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\n" ); document.write( "\n" ); document.write( "in the equation x + y = 340,000, replace x with 1.125y to get 1.125y + y = 340,000.\r
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\n" ); document.write( "\n" ); document.write( "combine like terms to get 2.125y = 340,000.\r
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\n" ); document.write( "\n" ); document.write( "solve for y to get y = 340,000 / 2.125 = 160,000.\r
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\n" ); document.write( "\n" ); document.write( "since x = 1.125y, you get x = 1.125 * 160,000 = 180,000.\r
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\n" ); document.write( "\n" ); document.write( "the amount invested at 8% is 180,000.\r
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\n" ); document.write( "\n" ); document.write( "the amound invested at 9% is 160,000\r
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\n" ); document.write( "\n" ); document.write( ".08 * 180,000 = 14,400.\r
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\n" ); document.write( "\n" ); document.write( ".09 * 160,000 = 14,400.\r
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\n" ); document.write( "\n" ); document.write( "the income is the same, so the solution is good.\r
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