document.write( "Question 86756: 1.FIND THE CONSTANT TERM THAT SHOULD BE ADDED TO MAKE THE FOLLOWING EXPRESSION A PERFECT SQUARE TRINOMIAL....
\n" ); document.write( "X^2+5X\r
\n" ); document.write( "\n" ); document.write( "2. SOLVE BY COMPLETING THE SQUARE...
\n" ); document.write( "X^2-4X+4=0\r
\n" ); document.write( "\n" ); document.write( "3. EVALUATE IF POSSIBLE...
\n" ); document.write( "-3 ROOT OF 64\r
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\n" ); document.write( "\n" ); document.write( "THANKS IN ADVCANCE FOR ALL OF YOUR HELP!!!
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Algebra.Com's Answer #62766 by tutorcecilia(2152)\"\" \"About 
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1.FIND THE CONSTANT TERM THAT SHOULD BE ADDED TO MAKE THE FOLLOWING EXPRESSION A PERFECT SQUARE TRINOMIAL....
\n" ); document.write( "X^2+5X
\n" ); document.write( "\"%28x%5E2%2B5x%2B%285%2F2%29%5E2%29\"=\"%28%285%2F2%29%5E2%29\" [divide the second term by (2) and square the fraction; add the term to both sides of the equation]
\n" ); document.write( "ANSWER: \"%28%285%2F2%29%5E2%29\" or \"%2825%2F4%29\"
\n" ); document.write( ".\r
\n" ); document.write( "\n" ); document.write( "2. SOLVE BY COMPLETING THE SQUARE...
\n" ); document.write( "X^2-4X+4=0
\n" ); document.write( "\"%28x%5E2-4x%2B4-4%29\"=0-4 [subtract/add the last term to both sides of the equation]
\n" ); document.write( ".
\n" ); document.write( " \"%28x%5E2-4x%29\"= -4
\n" ); document.write( " \"%28x%5E2-4x%2B%284%2F2%29%5E2%29\"= -4 + (4/2)^2 [divide the second term by (2) and square the fraction; add the term to both sides of the equation]
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\n" ); document.write( "\"%28x%5E2-4x%2B%284%2F2%29%5E2%29\"= \"%28-4%2B%282%29%5E2%29%29\" [simplify the left-hand side]
\n" ); document.write( "\"%28x%5E2-4x%2B%284%2F2%29%5E2%29\"= \"%280%29\"
\n" ); document.write( "\"%28x%5E2-4x%2B%284%2F2%29%5E2%29\"= 0
\n" ); document.write( "\"%28x-%284%2F2%29%29%28x-%284%2F2%29%29\"= 0 [expand the left-side]
\n" ); document.write( "\"%28x-2%29%29%28x-2%29%29\"= 0 [simplify the left-side if possible]
\n" ); document.write( "\"%28x-2%29%5E2%29\"= 0
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\n" ); document.write( "\"%28sqrt%28x-2%29%5E2%29\"= \"%28sqrt%280%29%29\" [find the square root of both sides and simplify]
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\n" ); document.write( "x-2= 0 [solve for the x-term]
\n" ); document.write( "x-2+2= +2
\n" ); document.write( "x= 2
\n" ); document.write( ".\r
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\n" ); document.write( "\n" ); document.write( "3. EVALUATE IF POSSIBLE...
\n" ); document.write( "-3 ROOT OF 64
\n" ); document.write( "= -4 [because (-4)(-4)(-4)=-64
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