document.write( "Question 1011843: xy=12, (x^2+y^2)=25 then what is the value of (x+y)2^2 \n" ); document.write( "
Algebra.Com's Answer #627642 by MathTherapy(10552)\"\" \"About 
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xy=12, (x^2+y^2)=25 then what is the value of (x+y)2^2
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\"xy+=+12\"   ;   \"x%5E2+%2B+y%5E2+=+25\"\r
\n" ); document.write( "\n" ); document.write( "Observing \"x%5E2+%2B+y%5E2+=+25\", it's obvious that x and y MUST be 3 and 4
\n" ); document.write( "Likewise x and y MUST be 3 and 4 as xy = 12\r
\n" ); document.write( "\n" ); document.write( "Proving this, we get:
\n" ); document.write( "\"%28x+%2B+y%29%5E2+=+x%5E2+%2B+2xy+%2B+y%5E2\" --------> \"x%5E2+%2B+y%5E2+%2B+2xy\", which becomes: 25 + 2(12) = 25 + 24 = 49
\n" ); document.write( "Since \"%28x+%2B+y%29%5E2+=+49\", then x + y = 7 ------ Square root of each side was taken\r
\n" ); document.write( "\n" ); document.write( "I don’t know what \"%28x+%2B+y%292%5E2\" means but you should be able to determine what’s needed since it was found that:
\n" ); document.write( "\"%28x+%2B+y%29%5E2+=+49\" & \"x+%2B+y+=+7\", and the following were given: \"xy+=+12\" & \"%28x%5E2+%2B+y%5E2%29+=+25+\" \n" ); document.write( "
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