document.write( "Question 1011839: the perimeter of a triangle is 79.75 inches. the second side of the triangle is half as big as the first side the third side is 7.25 inches greater than the first side. what is the length of the longest side of the triangle. give your answer as a decimal \n" ); document.write( "
Algebra.Com's Answer #627638 by stanbon(75887)\"\" \"About 
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the perimeter of a triangle is 79.75 inches. the second side of the triangle is half as big as the first side the third side is 7.25 inches greater than the first side. what is the length of the longest side of the triangle. give your answer as a decimal
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\n" ); document.write( "Let the sides be a,b,c
\n" ); document.write( "Equations:
\n" ); document.write( "a + b + c = 79.75
\n" ); document.write( "b = a/2
\n" ); document.write( "c = a + 7.25
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\n" ); document.write( "Substitute and solve for \"a\":
\n" ); document.write( "a + a/2 + a + 7.25 = 79.75
\n" ); document.write( "(5/2)a = 72.50
\n" ); document.write( "---
\n" ); document.write( "a = 145/5
\n" ); document.write( "a = 29 inches
\n" ); document.write( "b = 14.5 inches
\n" ); document.write( "c = 36.25 inches
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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