document.write( "Question 1011811: Chary invested an amount at 12% and twice as much at 9%. Her annual interest at 9% is P10140 more than her annual interest on 12%. How much is invested at each rate? \n" ); document.write( "

Algebra.Com's Answer #627574 by josgarithmetic(39617) $\"\"$ $\"About$

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Amount Invested        Amount of Interest\r\n" );
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document.write( "2x at 9%               0.09*2x\r\n" );
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document.write( "x at 12%               0.12*x

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\n" ); document.write( "\n" ); document.write( "The description transcribed into an equation will be $\"0.09%2A2x=10140%2B0.12x\"$ . \n" ); document.write( "

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