document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1011785>Question 1011785</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many pure acid must be added to a 2L of a 10% solution to obtain a mixture that is 20% acid? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #627540 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=627540\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's call the final amount x. So we want to get 0.20x<BR>\n" );
document.write( "Since we have 2 at 0.10, the amount of pure acid will be x-2:<BR>\n" );
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document.write( "0.10(2)+1(x-2)= 0.20x<BR>\n" );
document.write( "0.20+x-2= 0.20x<BR>\n" );
document.write( "-1.8= -0.8x rearrange (for no reason, just to make it look proper)<BR>\n" );
document.write( "-0.8x= -1.8 Divide both sides by -0.8 (and remember that -/-= +)<BR>\n" );
document.write( "x= 2.25 liters of pure acid are need </SPAN>\n" );
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