document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1011774>Question 1011774</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The owner of men's clothing store bought six belts and eight hats for $140. A week later, at the same prices, he bought nine belts and six hats for $132. Find the price of a belt and the price of a hat.\r<BR>\n" );
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document.write( "WHAT I KNOW<BR>\n" );
document.write( "    The equation for the first time he bought his items wod be 6b+8h=140<BR>\n" );
document.write( "The b would stand for belts while the h would stand for hats<BR>\n" );
document.write( "The other equation would be 9b+6h=132. I know that i have to multiply a number so o e of the variables would be the same but i do not understand the rest. Thank you for looking through my question. Have a nice day </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #627529 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=627529\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you have two equations that have to be solved simultaneously.\r<BR>\n" );
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document.write( "the two equations are:\r<BR>\n" );
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document.write( "6b + 8h = 140<BR>\n" );
document.write( "9b + 6h = 132\r<BR>\n" );
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document.write( "multiply both sides of the first equation by 3 and multiply both sides of the second equation by 2.\r<BR>\n" );
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document.write( "you will get:\r<BR>\n" );
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document.write( "18b + 24h = 420<BR>\n" );
document.write( "18b + 12h = 264\r<BR>\n" );
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document.write( "subtract the second equation from the first to get:\r<BR>\n" );
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document.write( "0b + 12h = 156\r<BR>\n" );
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document.write( "simplify to get 12h = 156\r<BR>\n" );
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document.write( "divide both sides of this equation by 12 to get:\r<BR>\n" );
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document.write( "h = 78\r<BR>\n" );
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document.write( "the cost of a hat is 13 dollars.\r<BR>\n" );
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document.write( "go back to one of the original equations and replace h with 13 and solve for b.\r<BR>\n" );
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document.write( "6b + 8h = 140 becomes 6b + 8*13 = 140 which becomes 6b + 104 = 140.\r<BR>\n" );
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document.write( "subtract 104 from both sides of this equation to get 6b = 140 - 104.\r<BR>\n" );
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document.write( "simplify to get 6b = 36.\r<BR>\n" );
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document.write( "divide both sides of this equation by 6 to get b = 6.\r<BR>\n" );
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document.write( "the cost of a hat is 13 dollars.<BR>\n" );
document.write( "the cost of a belt is 6 dollars.\r<BR>\n" );
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document.write( "replace both original equations with 13 dollars for h and 6 dollars for b to get:\r<BR>\n" );
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document.write( "6b + 8h = 140 becomes 6*6 + 8*13 = 140 which becomes 36 + 104 = 140 which becomes 140 = 140 which is true.\r<BR>\n" );
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document.write( "9b + 6h = 132 becomes 9*6 + 6*13 = 132 which becomes 54 + 78 = 132 which becomes 132 = 132 which is true.\r<BR>\n" );
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document.write( "the numbers check out ok.\r<BR>\n" );
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document.write( "your solution is the cost of a belt is 6 dollars and the cost of a hat is 13 dollars.\r<BR>\n" );
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document.write( "here's a reference on how to solve equations simultaneously.\r<BR>\n" );
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document.write( "<a  rel=nofollow HREF= \"http://www.purplemath.com/modules/systlin1.htm\" target=\"_blank\">http://www.purplemath.com/modules/systlin1.htm</a>\r<BR>\n" );
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document.write( " </SPAN>\n" );
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