document.write( "Question 1011768: 3.What if the desired final mixture was changed to yield a 35% mixture containing pure lemon juice? \r
\n" ); document.write( "\n" ); document.write( "a.How many gallons of a 20% solution should be mixed with 15 gallons of a 70% solution to yield a final mixture of lemonade containing 35% of pure lemon juice? Write your answer in complete sentences. Show all work.\r
\n" ); document.write( "\n" ); document.write( "b.How many gallons of lemonade would this combination yield? Write your answer in complete sentences. Show all work
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Algebra.Com's Answer #627524 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
a.How many gallons of a 20% solution should be mixed with 15 gallons of a 70% solution to yield a final mixture of lemonade containing 35% of pure lemon juice? Write your answer in complete sentences. Show all work.
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\n" ); document.write( "0.20x + 0.70*15 = 0.35*(x+15)
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\n" ); document.write( "20x + 70*15 = 35x + 35*15
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\n" ); document.write( "15x = 35*15
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\n" ); document.write( "x = 35 gallons (amt of 20% solution needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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\n" ); document.write( "b.How many gallons of lemonade would this combination yield? Write your answer in complete sentences. Show all work
\n" ); document.write( "Ans: x+15 = 35+15 = 50 gallons
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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