document.write( "Question 1011768: 3.What if the desired final mixture was changed to yield a 35% mixture containing pure lemon juice? \r
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document.write( "a.How many gallons of a 20% solution should be mixed with 15 gallons of a 70% solution to yield a final mixture of lemonade containing 35% of pure lemon juice? Write your answer in complete sentences. Show all work.\r
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document.write( "b.How many gallons of lemonade would this combination yield? Write your answer in complete sentences. Show all work \n" );
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Algebra.Com's Answer #627524 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! a.How many gallons of a 20% solution should be mixed with 15 gallons of a 70% solution to yield a final mixture of lemonade containing 35% of pure lemon juice? Write your answer in complete sentences. Show all work. \n" ); document.write( "------ \n" ); document.write( "0.20x + 0.70*15 = 0.35*(x+15) \n" ); document.write( "----- \n" ); document.write( "20x + 70*15 = 35x + 35*15 \n" ); document.write( "----- \n" ); document.write( "15x = 35*15 \n" ); document.write( "----- \n" ); document.write( "x = 35 gallons (amt of 20% solution needed) \n" ); document.write( "------------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "--------------- \n" ); document.write( "b.How many gallons of lemonade would this combination yield? Write your answer in complete sentences. Show all work \n" ); document.write( "Ans: x+15 = 35+15 = 50 gallons \n" ); document.write( "----------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "----------- \n" ); document.write( " |