document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1011766>Question 1011766</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1.The boys mixed 10 gallons of the 20% pure lemon juice mix and 10 gallons of the 70% pure lemon juice mix, because they wanted 20 gallons of lemonade at a 40% lemon juice mixture. They thought that because 40% was almost halfway between 20% and 70%, they should just mix equal parts of both, but the lemonade turned out too tart. How much of each should they have used to get a final mixture of 20 gallons at 40% lemon juice?  Write your answer in complete sentences. Show all work. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #627517 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=627517\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The boys mixed 10 gallons of the 20% pure lemon juice mix and 10 gallons of the 70% pure lemon juice mix, because they wanted 20 gallons of lemonade at a 40% lemon juice mixture. They thought that because 40% was almost halfway between 20% and 70%, they should just mix equal parts of both, but the lemonade turned out too tart. How much of each should they have used to get a final mixture of 20 gallons at 40% lemon juice? Write your answer in complete sentences. Show all work. <BR>\n" );
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document.write( "Quantity Equation: t + s = 20 gallons<BR>\n" );
document.write( "Lemon content Eq: 20t+70s = 40*20 gallons<BR>\n" );
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document.write( "Modify for elimination:<BR>\n" );
document.write( "2t + 2s = 2*20<BR>\n" );
document.write( "2t + 7s = 4*20<BR>\n" );
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document.write( "Subtract and solve for \"s\":<BR>\n" );
document.write( "5s = 2*20<BR>\n" );
document.write( "s = 8 gallons (amt. of 70% mix needed)<BR>\n" );
document.write( "t = 20-8 = 12 gallons (amt of 20% mix needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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