document.write( "Question 1011755: Triangle TJK is a 45 degree-45 degree-90 degree triangle with right angle at J. What are the coordinates of T in Quadrant II For J(-2,-3) and K(3,-3). \n" ); document.write( "

Algebra.Com's Answer #627504 by josmiceli(19441) $\"\"$ $\"About$

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The side JT is perpendicular to the
\n" ); document.write( "side JK.
\n" ); document.write( "Find the slope of JK:
\n" ); document.write( "J(-2,-3) and K(3,-3)
\n" ); document.write( " $\"+m%5B1%5D+=+%28+-3+-%28-3%29+%29+%2F+%28+3+-%28-2%29+%29+\"$
\n" ); document.write( " $\"+m%5B1%5D+=+0+\"$
\n" ); document.write( "Zero slope is a horizontal line, so any
\n" ); document.write( "line perpendicular to it is a vertical line
\n" ); document.write( "-----------------
\n" ); document.write( "The side JT goes through J( -2,-3 ), so
\n" ); document.write( "it's equation is $\"+x+=+-2+\"$
\n" ); document.write( "------------------------
\n" ); document.write( "The length of horizontal line JK is:
\n" ); document.write( " $\"+d+=+sqrt%28+%28+3+-%28-2%29%29%5E2+%2B+%28+-3+-%28-3%29+%29%5E2+%29+\"$
\n" ); document.write( " $\"+d+=+sqrt%28+5%5E2+%2B+0%5E2+%29+\"$
\n" ); document.write( " $\"+d+=+sqrt%28+25+%29+\"$
\n" ); document.write( " $\"+d+=+5+\"$
\n" ); document.write( "-----------
\n" ); document.write( "Since it's a 45-45-90 triangle, side JT also
\n" ); document.write( "is $\"+5+\"$ units long.
\n" ); document.write( "It's a vertical line and the x-coordinate is $\"+x+=+-2+\"$
\n" ); document.write( "Point T is:
\n" ); document.write( "T( -2, 5 )
\n" ); document.write( "Note this is in quadrant 2 also \n" ); document.write( "

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