document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=12341>Question 12341</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please I need a step by step strategy for adding and substracting rational expressions that have different denominators. In addition, please provide an example problem.  Please I need to understand this for a test tonight. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6275 by </B><A HREF=/tutors/aboutme.mpl?userid=askmemath><B>askmemath(368)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=askmemath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6275\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's say you want to add a/b and c/d\r<BR>\n" );
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document.write( "Then you can add as follows\r<BR>\n" );
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document.write( "(axc + bxd)/bxd\r<BR>\n" );
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document.write( "Let's try with 3/4 + 5/6\r<BR>\n" );
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document.write( "We re-write from above as \r<BR>\n" );
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document.write( "(3x6 + 5x4)/4x6\r<BR>\n" );
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document.write( "=(18+20)/24\r<BR>\n" );
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document.write( "=38/24\r<BR>\n" );
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document.write( "=19/12\r<BR>\n" );
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document.write( "Hope this helps. </SPAN>\n" );
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