document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1011749>Question 1011749</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the principle is 15,300 and the rate is 3.5% and the simple interest is 2,142.00, what is the time, in regards to the missing value?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #627498 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=627498\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> interest = P.r.t<BR>\n" );
document.write( "2142= 15300*0.035*t multiply on left:<BR>\n" );
document.write( "2142= 535.50*t Divide both sides by 535.50<BR>\n" );
document.write( "2141/535.50= (535.50*t)/535.50 Divide on left, and on right 535.50 multiplying and dividing cancel each other, and you get:<BR>\n" );
document.write( "4= t or<BR>\n" );
document.write( "t= 4 is the number of periods (if the interest is annual, then 4 years, if the interest is quarterly, then 4 quarters and so on. If the interest is daily then 4 days. You get the idea)<BR>\n" );
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