document.write( "Question 12340: 13/100 = 39/x \n" ); document.write( "
Algebra.Com's Answer #6274 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
\"13%2F100+=+39%2Fx\"
\n" ); document.write( "\"13x%2F100+=+39\"
\n" ); document.write( "\"13x+=+39%2A100\"
\n" ); document.write( "\"13x+=+3900\"
\n" ); document.write( "\"x+=+3900%2F13\"
\n" ); document.write( "\"x+=+300\"\r
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\n" ); document.write( "\n" ); document.write( "or for soemthing this \"simple\" in structure, you could just scale up the lefthand side as follows...\r
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\n" ); document.write( "\n" ); document.write( "\"13%2F100+=+39%2Fx\"
\n" ); document.write( "\"39%2F300+=+39%2Fx\"\r
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\n" ); document.write( "\n" ); document.write( "so comparing...x must be 300\r
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\n" ); document.write( "\n" ); document.write( "jon.
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