document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1011670>Question 1011670</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the numerator and the denominator of a fraction is 20. If the numerator is increased by 3 and the denominator is decreased by 2, the value of the resulting fraction is 3/4. Find the original fraction. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #627395 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=627395\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=numerator<BR>\n" );
document.write( "20-x=denominator<BR>\n" );
document.write( "(x+3)/(20-x-2)=3/4<BR>\n" );
document.write( "cross multiply<BR>\n" );
document.write( "4(x+3)=3(18-x)<BR>\n" );
document.write( "distribute<BR>\n" );
document.write( "4x+12=54-3x<BR>\n" );
document.write( "7x=42<BR>\n" );
document.write( "x=6<BR>\n" );
document.write( "The fraction is 6/14<BR>\n" );
document.write( "9/12=3/4 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );