document.write( "Question 1011657: 3/5 of the beads in abox are yellow beads. The rest are red beads and blue beads.
\n" ); document.write( "There are twice as many yellow beads as red beads. There are 30 more red beads than blue beads. Find the total no of yellow beads and ref beads. \n" ); document.write( "
Algebra.Com's Answer #627389 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
3/5 of the beads in abox are yellow beads. The rest are red beads and blue beads.
\n" ); document.write( "There are twice as many yellow beads as red beads. There are 30 more red beads than blue beads. Find the total no of yellow beads and red beads.
\n" ); document.write( "-----
\n" ); document.write( "Equations:
\n" ); document.write( "(3/5)(r + b + y) = y
\n" ); document.write( "y = 2r
\n" ); document.write( "r = b+30
\n" ); document.write( "-----
\n" ); document.write( "Solve for r, b, and y
\n" ); document.write( "---------------------------
\n" ); document.write( "(3/5)((y/2) + (y/2)-30 + y) = y
\n" ); document.write( "(3/5)(2y-30) = y
\n" ); document.write( "2y-30 = (5/3)y
\n" ); document.write( "(1/3)y = 30
\n" ); document.write( "y = 90 (# of yellow)
\n" ); document.write( "r = y/2 = 45 (# of red)
\n" ); document.write( "-----------------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "-------------\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );