document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1011645>Question 1011645</A>: <I><SPAN STYLE=\"word-break: break-all;\"> C4. #16\r<BR>\n" );
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document.write( "Solve the equation <BR>\n" );
document.write( "x^3-13x^2+47x-35=0 given that 1 is zero of f(x)=x^3-13x^2+47x-35 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #627375 by </B><A HREF=/tutors/aboutme.mpl?userid=mathmate><B>mathmate(429)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathmate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mathmate><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=627375\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  <BR>\n" );
document.write( "Question:<BR>\n" );
document.write( "Solve the equation <BR>\n" );
document.write( "x^3-13x^2+47x-35=0 given that 1 is zero of f(x)=x^3-13x^2+47x-35<BR>\n" );
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document.write( "Solution:<BR>\n" );
document.write( "Knowing that 1 is a zero (as evident by the factor theorem), we divide the expression by (x-1) to get<BR>\n" );
document.write( "(x^3-13x^2+47x-35)/(x-1)=x^2-12x+35<BR>\n" );
document.write( "the latter factorizes into (x-7)(x-5)<BR>\n" );
document.write( "from which we can conclude that the solutions to x^3-13x^2+47x-35=0 are<BR>\n" );
document.write( "x={1,5,7} </SPAN>\n" );
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