document.write( "Question 1011621: John can walk at 5 km/h and run at 15 km/h. A and B are two stops on a road. Both are 2 km from John’s home.
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document.write( "a)The bus leaves from A in 15 minutes. How far can John walk from home before he has to run to catch the bus?
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document.write( "b)It takes the bus 3 minutes to travel from A to B. If John catches the bus at B, how much less running does John have to do?
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Algebra.Com's Answer #627359 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! John can walk at 5 km/h and run at 15 km/h. \n" ); document.write( " A and B are two stops on a road. \n" ); document.write( " Both are 2 km from John’s home.\r \n" ); document.write( "\n" ); document.write( "a)The bus leaves from A in 15 minutes. \n" ); document.write( " How far can John walk from home before he has to run to catch the bus? \n" ); document.write( ": \n" ); document.write( "change 15 min to .25 hrs ( we're dealing in km/hr) \n" ); document.write( "let t = time spent walking in hrs \n" ); document.write( "then \n" ); document.write( "(.25-t) = time spent running in hrs \n" ); document.write( ": \n" ); document.write( "Write a distance equation; dist = speed * time \n" ); document.write( "walk dist + run dist = 2 km \n" ); document.write( "5t + 15(.25-t) = 2 \n" ); document.write( "5t + 3.75 - 15t \n" ); document.write( "5t - 15t = 2 - 3.75 \n" ); document.write( "-10t = -1.75 \n" ); document.write( "t = -1.75/-10 \n" ); document.write( "t = +.175 hrs walking \n" ); document.write( "How far can he walk in this time? \n" ); document.write( "5 * .175 = .875 km walking before he has to run 1.125 km \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "b)It takes the bus 3 minutes to travel from A to B. \n" ); document.write( " If John catches the bus at B, how much less running does John have to do? \n" ); document.write( ": \n" ); document.write( "That means he has 3 more minutes to catch the bus at B, or 18 min \n" ); document.write( "Change 18 min to hrs, 18/60 = .3 hrs \n" ); document.write( ": \n" ); document.write( "let t = time spent walking in hrs \n" ); document.write( "then \n" ); document.write( "(.3-t) = time spent running in hrs \n" ); document.write( ": \n" ); document.write( "Write a distance equation; dist = speed * time \n" ); document.write( "walk dist + run dist = 2 km \n" ); document.write( "5t + 15(.3-t) = 2 \n" ); document.write( "5t + 4.5 - 15t \n" ); document.write( "5t - 15t = 2 - 4.5 \n" ); document.write( "-10t = -2.5 \n" ); document.write( "t = -2.5/-10 \n" ); document.write( "t = +.25 hrs walking \n" ); document.write( "How far can he walk in this time? \n" ); document.write( "5 * .25 = 1.25 km walking before he has to run .75 km \n" ); document.write( "Find how much less running 1.125 - .75 = .375 km less running \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "See if that checks out. find the distance walking and distance running \n" ); document.write( "walking: .25*5 = 1.25 km \n" ); document.write( "running: (.3-.25)*15 = .75 km \n" ); document.write( "----------------------------- \n" ); document.write( "Total distance: 2 km \n" ); document.write( " |