document.write( "Question 1011590: Find the equation of the locus of a point p (x,y) when:\r
\n" ); document.write( "\n" ); document.write( "1. the distance of P from the line y=-5 is three quarters of its distance from the line x = 2\r
\n" ); document.write( "\n" ); document.write( "2. The distacne of P from the line x= -3 is two fifths of its distance from the line y= -1\r
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Algebra.Com's Answer #627302 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
The two questions are very much alike. Question number 1 gives the horizontal line y=-5 and the vertical line x=2; these are the more general points (x,-5) and (2,y). Fit the description into the Distance Formula:\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%28%28y%2B5%29%5E2%29=%283%2F4%29sqrt%28%28x-2%29%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"y%2B5=0%2B-+%283%2F4%29%28x-2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Simplify into the two equations in whatever form you want.
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\n" ); document.write( "\"y%2B5=-%283%2F4%29%28x-2%29\"
\n" ); document.write( "\"y=-%283%2F4%29x%2B3%2F2-5\"
\n" ); document.write( "\"highlight%28y=-%283%2F4%29x-7%2F2%29\"------one of the lines
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\n" ); document.write( "\"y%2B5=%283%2F4%29%28x-2%29\"
\n" ); document.write( "\"y%2B5=%283%2F4%29x-3%2F2\"
\n" ); document.write( "\"y=%283%2F4%29x-3%2F2-10%2F2\"
\n" ); document.write( "\"highlight%28y=%283%2F4%29x-13%2F2%29\"-----------other line
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