document.write( "Question 1011575: f(x)=x^4+2x^3+x^2+8x-12\r
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Algebra.Com's Answer #627294 by MathTherapy(10557)\"\" \"About 
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f(x)=x^4+2x^3+x^2+8x-12\r
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\n" ); document.write( "\n" ); document.write( "I need to find all of the actual zeros of this function, including the complex. Thanks.
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Using the rational root theorem, you'll find that 1 and - 3 are 2 of the roots. 
\n" ); document.write( "Therefore, 2 of its factors are: (x - 1) and (x + 3), which combine to give the factor: \"x%5E2+%2B+2x+-+3\"
\n" ); document.write( "Dividing \"x%5E4+%2B+2x%5E3+%2B+x%5E2+%2B+8x+-+12\" by the factor: \"x%5E2+%2B+2x+-+3\" (\"%28x%5E4+%2B+2x%5E3+%2B+x%5E2+%2B+8x+-+12%29%2F%28x%5E2+%2B+2x+-+3%29\") by long division or synthetic division results in the other factor: \"x%5E2+%2B+4\"
\n" ); document.write( "\"x%5E2+%2B+4\" = \"%28x+-+2i%29%28x+%2B+2i%29\". Thus, the other 2 roots are: \"%22+%22%2B-+2i\"
\n" ); document.write( "Therefore, roots, or zeroes are: \"highlight_green%28system%28x+=+1%2C+x+=+-+3%2C+x+=+%22+%22%2B-+2i%29%29\" \n" ); document.write( "
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