Algebra.Com's Answer #627291 by MathTherapy(10552)![\"\"](\"/images/stars/stars-13.gif\")  
You can put this solution on YOUR website!
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document.write( "Segment JK is exactly 15 units long. Point J is located at (10,-8). Point K is located in quadrant 2 and is one unit above the x-axis. What are the coordinates of point K? (May someone help me please and thank you)\r
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document.write( "* this is what I did before I confused myself:
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document.write( "After you add them together you have to find the square root, the square is the distance.(d stands for distance) I couldn't get the square root symbol I'm sorry.
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document.write( "d=15. 15=(x2-10)²+(y2-(-8))²
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document.write( "15=(x2-10)²+(9)²
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document.write( "15=(x2-10)²+(9)²
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document.write( "15=(x2-10)²+81
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document.write( "You're on the right track, but you forgot to square the 15!
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document.write( " <-------- This is what you have
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document.write( " <------- This is what you should have
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document.write( "Continue to solve for  from here. You should get 2 values for , but one is positive and the
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document.write( "other is negative. You need the negative value since K is in the 2nd quadrant, where x is negative. \n" );
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