document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=86699>Question 86699</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This is from a worksheet. I do not understand how to do this at all. I have notes from my instructor but they are not very clear to me about this type of problem. The directions are as follows: \"Find all the real number solutions for each equation.\" Here is my first equation. \r<BR>\n" );
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document.write( "x^5-x=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #62729 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=62729\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Factor, factor, factor...\r<BR>\n" );
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document.write( "x^5-x=0 factors into x(x^4-1)=0 ... so x=0 is one solution\r<BR>\n" );
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document.write( "x^4-1=0 factors into (difference of 2 squares) (x^2+1)(x^2-1)=0\r<BR>\n" );
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document.write( "x^2-1=0 factors into (x+1)(x-1)=0 ... so x=-1 and x=1 are solutions\r<BR>\n" );
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document.write( "x^2+1=0 ... x^2=-1 ... no real solutions </SPAN>\n" );
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