document.write( "Question 1011575: f(x)=x^4+2x^3+x^2+8x-12\r
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\n" ); document.write( "\n" ); document.write( "I need to find all of the actual zeros of this function, including the complex. Thanks.
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Algebra.Com's Answer #627280 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
One can guess, using possible roots of +/-1,+/-2, +/-3, +/-4, +/-6, and +/-12.
\n" ); document.write( "The latter two are unlikely.
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\n" ); document.write( "1:1//2//1//8//-12
\n" ); document.write( "=1=3=4=12=/0
\n" ); document.write( "(x-1) is a factor
\n" ); document.write( "What is left is x^3+3x^2+4x+12
\n" ); document.write( "-3:1//3//4//12
\n" ); document.write( "==1/0/4//0
\n" ); document.write( "(x+3) is a factor
\n" ); document.write( "left is x^2+4, which factors into (x+2i) and (x-2i)
\n" ); document.write( "The zeros are 1,-3, +2i,-2i
\n" ); document.write( "\"graph%28300%2C200%2C-10%2C10%2C-100%2C100%2Cx%5E4%2B2x%5E3%2Bx%5E2%2B8x-12%29\"
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