document.write( "Question 1011575: f(x)=x^4+2x^3+x^2+8x-12\r
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Algebra.Com's Answer #627279 by ikleyn(52908)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "f(x)=x^4+2x^3+x^2+8x-12 \r
\n" ); document.write( "\n" ); document.write( "I need to find all of the actual zeros of this function, including the complex. Thanks.
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document.write( "\"x%5E4%2B2x%5E3%2Bx%5E2%2B8x-12\" = \"0\".\r\n" );
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document.write( "It is easy to check that x = 1 is the root. \r\n" );
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document.write( "It means that the left side polynomial has the factor (x-1).\r\n" );
document.write( "Make long division of \"x%5E4%2B2x%5E3%2Bx%5E2%2B8x-12\" by (x-1). You will get \r\n" );
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document.write( "\"%28x%5E4%2B2x%5E3%2Bx%5E2%2B8x-12%29%2F%28x-1%29\" = \"x%5E3+%2B+3x%5E2+%2B+4x+%2B+12\".\r\n" );
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document.write( "The polynomial \"x%5E3+%2B+3x%5E2+%2B+4x+%2B+12\" has the root x = -3. (Check it).\r\n" );
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document.write( "Then this polynomial has the factor (x+3).\r\n" );
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document.write( "Make the long division again and get the quotient, which is the quadratic polynomial this time.\r\n" );
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document.write( "I hope that you can complete yourself the assignment from this point.\r\n" );
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