document.write( "Question 1011576: f(x)=2x^3+5x^2-x-6\r
\n" ); document.write( "\n" ); document.write( "I need to find the actual zeros on my calculator. Then, show the correct factorization of the function. Thanks. \n" ); document.write( "
Algebra.Com's Answer #627278 by Boreal(15235)\"\" \"About 
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Enter the equation under Y=
\n" ); document.write( "use window -5<=x<=5
\n" ); document.write( "-10<=y<=10
\n" ); document.write( "scl 1
\n" ); document.write( "see what looks like a clear root at 1
\n" ); document.write( "Check that 2+5-1-6=0
\n" ); document.write( "(x-1) is a factor.
\n" ); document.write( "The other root is near -2. Check f(-2):-16+20+2-6
\n" ); document.write( "There is a third root that is not an integer.
\n" ); document.write( "divide x-1 into 2x^3+5x^2-x-6;
\n" ); document.write( "synthetic division
\n" ); document.write( "1/2==5==-1==-6
\n" ); document.write( "2===7==6===0
\n" ); document.write( "so the second factor is (2x^2+7x+6)
\n" ); document.write( "This factors into (2x+3)(x+2); function's factors are (x-1)(2x+3)(x+2)
\n" ); document.write( "roots are -2 and -1.5.
\n" ); document.write( "One can change the window to look at x between -1 and -2.
\n" ); document.write( "Use 2nd Trace to get calc, and 2 for zero. Put the cursor below the x-axis near where the function climbs above. Left bound: Enter. Move it to the right side and hit Enter for right bound. When Guess appears on screen, hit enter, and -1.5 will appear.
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