document.write( "Question 1011570: Segment JK is exactly 15 units long. Point J is located at (10,-8). Point K is located in quadrant 2 and is one unit above the x-axis. What are the coordinates of point K? (May someone help me please and thank you)\r
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document.write( "* this is what I did before I confused myself:
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document.write( "After you add them together you have to find the square root, the square is the distance.(d stands for distance) I couldn't get the square root symbol I'm sorry.
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document.write( "d=15. 15=(x2-10)²+(y2-(-8))²
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document.write( "15=(x2-10)²+(9)²
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document.write( "15=(x2-10)²+(9)²
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document.write( "15=(x2-10)²+81 \n" );
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Algebra.Com's Answer #627267 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! You have the given point J( 10, -8 ). The signs ( +, - ) \n" ); document.write( "tell you it is in the 4th quadrant. \n" ); document.write( "The other point K looks like ( x, 1 ) \n" ); document.write( "------------------------------ \n" ); document.write( "If you used J as a center and made part of a circle with \n" ); document.write( "radius = 15 in the 2nd quadrant, it crosses the line \n" ); document.write( " \n" ); document.write( "---------------------------- \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "I notice that \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "so that works \n" ); document.write( "Point K is ( -2, 1 ) \n" ); document.write( "------------------ \n" ); document.write( "check answer: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OK \n" ); document.write( " |