document.write( "Question 86697: SOLVE...
\n" ); document.write( "1. ROOT OF 4X+12-4=0\r
\n" ); document.write( "\n" ); document.write( "SIMPLIFY....
\n" ); document.write( "1. ROOT OF 50 OVER ROOT OF 2\r
\n" ); document.write( "\n" ); document.write( "SIMPLIFY...
\n" ); document.write( "1. 6ROOT OF 6X+ 3 ROOT OF 6X\r
\n" ); document.write( "\n" ); document.write( "EVALUATE IF POSSIBLE...
\n" ); document.write( "1.-3 ROOT OF 64
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Algebra.Com's Answer #62722 by ankor@dixie-net.com(22740)\"\" \"About 
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SOLVE...
\n" ); document.write( "1. ROOT OF 4X+12-4=0
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\n" ); document.write( "\"sqrt%284x%2B12%29\" - 4 = 0
\n" ); document.write( "\"sqrt%284x%2B12%29\" = +4; add 4 to both sides
\n" ); document.write( "4x + 12 = 16; squared both sides, (gets rid of the radical)
\n" ); document.write( "4x = 16 - 12; subtract 12 from both sides
\n" ); document.write( "4x = 4
\n" ); document.write( "x = 1
\n" ); document.write( "Substitute 1 for x in the original equation and see that it checks out
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\n" ); document.write( "SIMPLIFY....
\n" ); document.write( "1. ROOT OF 50 OVER ROOT OF 2
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\n" ); document.write( "\"sqrt%2850%29%2Fsqrt%282%29\"
\n" ); document.write( "\"sqrt%2825%2A2%29%2Fsqrt%282%29\"; find the perfect square inside the radical
\n" ); document.write( "\"5%2Asqrt%282%29%2Fsqrt%282%29\"; extract the sqrt of 25
\n" ); document.write( "Ans = 5; The \"sqrt%282%29\"'s cancel
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\n" ); document.write( "SIMPLIFY...
\n" ); document.write( "1. 6ROOT OF 6X+ 3 ROOT OF 6X
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\n" ); document.write( "\"6%2Asqrt%286x%29+%2B+3%2Asqrt%286x%29\" = \"9%2Asqrt%286x%29\"; sqrt(6x) are like terms, just add them
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\n" ); document.write( "EVALUATE IF POSSIBLE...
\n" ); document.write( "1.-3 ROOT OF 64
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\n" ); document.write( "\"-3%2Asqrt%2864%29\": we know the sqrt(64) = 8
\n" ); document.write( " -3 * 8 = -24
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