document.write( "Question 1011515: Good morning sir,please I want you to help me solve my question. If 5^-x=1\n,find 5^2x.
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Algebra.Com's Answer #627188 by Theo(13342)\"\" \"About 
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5^-x = 1/n\r
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\n" ); document.write( "\n" ); document.write( "since 5^-x is the same as 1/5^x, you get:\r
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\n" ); document.write( "\n" ); document.write( "1/5^x = 1/n\r
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\n" ); document.write( "\n" ); document.write( "multiply both sides of this equation by 5^x and multiply both sides of this equation by n to get:\r
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\n" ); document.write( "\n" ); document.write( "n = 5^x which is the same as 5^x = n.\r
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\n" ); document.write( "\n" ); document.write( "square both sides of this equation to get:\r
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\n" ); document.write( "\n" ); document.write( "(5^x)^2 = n^2\r
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\n" ); document.write( "\n" ); document.write( "since (5^x)^2 = 5^(2x), you get:\r
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\n" ); document.write( "\n" ); document.write( "5^(2x) = n^2\r
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\n" ); document.write( "\n" ); document.write( "that's your solution.\r
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