document.write( "Question 1011503: The sum of two numbers is 26. Twice the first plus half the second is 10. Find the numbers. \n" ); document.write( "

Algebra.Com's Answer #627177 by MathLover1(20850) $\"\"$ $\"About$

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let the numbers be $\"x\"$ and $\"y\"$
\n" ); document.write( "if the sum of two numbers is $\"26\"$ , we have\r
\n" ); document.write( "\n" ); document.write( " $\"x%2By=26\"$ ...solve for $\"x\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x=26-y\"$ .......eq.1\r
\n" ); document.write( "\n" ); document.write( "if twice the first ( $\"2x\"$ ) plus half the second ( $\"y%2F2\"$ ) is $\"10\"$ , we have \r
\n" ); document.write( "\n" ); document.write( " $\"2x%2By%2F2=10\"$ ...............substitute $\"x\"$ from eq.1\r
\n" ); document.write( "\n" ); document.write( " $\"2%2826-y%29%2By%2F2=10\"$ ......solve for $\"y\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"52-2y%2By%2F2=10\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"52-4y%2F2%2By%2F2-10=0\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"42-3y%2F2=0\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"42=3y%2F2\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"84=3y\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"84%2F3=y\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"highlight%28y=28%29\"$ \r
\n" ); document.write( "\n" ); document.write( "go to $\"x=26-y\"$ .......eq.1 and plug in $\"y\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x=26-28\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"highlight%28x=-2%29\"$ \r
\n" ); document.write( "\n" ); document.write( "so, your numbers are $\"highlight%28-2%29\"$ and $\"highlight%2828%29\"$ \r
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