document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=86695>Question 86695</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve algebraically using only one variable. The length of a rectangle is two more than twice its width. If the area of the rectangle is 84, find the length and width. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #62711 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=62711\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve algebraically using only one variable. The length of a rectangle is two more than twice its width. If the area of the rectangle is 84, find the length and width.<BR>\n" );
document.write( "------------<BR>\n" );
document.write( "Let the width be x; then the length is 2x+2<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "Area = width*length<BR>\n" );
document.write( "84 = x(2x+2)<BR>\n" );
document.write( "42 = x(x+1)<BR>\n" );
document.write( "x^2+x-42=0<BR>\n" );
document.write( "(x+7)(x-6)=0<BR>\n" );
document.write( "Positive answer:<BR>\n" );
document.write( "x=6 (width)<BR>\n" );
document.write( "2x+2 = 14 (length)<BR>\n" );
document.write( "==============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );