document.write( "Question 1011465: Find the equation of each family of lines described. Identify three members of the family and sketch them.
\n" ); document.write( "Perpendicular to the line 8x+y=6.
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Algebra.Com's Answer #627098 by MathLover1(20850) $\"\"$ $\"About$

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to find a line perpendicular to the line $\"8x%2By=6\"$ , write this equation in a slope-intercept form $\"y=mx%2Bb\"$ where $\"m\"$ is a $\"slope\"$ and $\"b\"$ is $\"y-intercept\"$ \r
\n" ); document.write( "\n" ); document.write( "we will need a slope $\"m\"$ because two lines are perpendicular if their slopes are negative reciprocal to each other\r
\n" ); document.write( "\n" ); document.write( " $\"y=highlight%28-8%29x%2B6\"$ =>a slope $\"m=-8\"$ \r
\n" ); document.write( "\n" ); document.write( "a line perpendicular to this line will have a slope $\"m%5Bp%5D=-%281%2F-8%29\"$ => $\"m%5Bp%5D=%281%2F8%29\"$ \r
\n" ); document.write( "\n" ); document.write( "so, $\"y=%281%2F8%29x\"$ is a line perpendicular to $\"8x%2By=6\"$ \r
\n" ); document.write( "\n" ); document.write( "for each line we need two points to graph them\r
\n" ); document.write( "\n" ); document.write( " $\"x\"$ | $\"y\"$ ....for $\"8x%2By=6\"$
\n" ); document.write( " $\"0\"$ | $\"6\"$ ........ $\"8%2A0%2By=6\"$ => $\"y=6\"$
\n" ); document.write( " $\"1\"$ | $\"-2\"$ ........ $\"8%2A%281%29%2By=6\"$ => $\"8%2By=6\"$ => $\"y=6-8\"$ => $\"y=-2\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"x\"$ | $\"y\"$ ....for $\"y=%281%2F8%29x\"$
\n" ); document.write( " $\"0\"$ | $\"0\"$ ........ $\"y=%281%2F8%290\"$ => $\"y=0\"$
\n" ); document.write( " $\"8\"$ | $\"1\"$ ........ $\"y=%281%2F8%298\"$ => $\"y=1\"$ \r
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