document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1011387>Question 1011387</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The letters of the word \"OKOTOKS\" are arranged. The number of arrangements that begins and ends with a vowel is ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #627038 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=627038\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if you put the vowels on the end, the number of ways you can do that is 1 because all the vowels are the same.\r<BR>\n" );
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document.write( "if you take away two of the o's because they're on the ends, then you are left with ktoks.\r<BR>\n" );
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document.write( "these can be arranged in 5! / 2! ways = (5*4*3*2!)/(2!) = 5*4*3 = 60 ways\r<BR>\n" );
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document.write( "60 ways in the middle * 1 way on the ends = 60 total ways.\r<BR>\n" );
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document.write( "that's my take.\r<BR>\n" );
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